(8x+3)(5x-9)-(6x-7)^2=4(x^2-1)

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Solution for (8x+3)(5x-9)-(6x-7)^2=4(x^2-1) equation: 



(8x+3)(5x-9)-(6x-7)^2=4(x^2-1)

We move all terms to the left:

(8x+3)(5x-9)-(6x-7)^2-(4(x^2-1))=0

We multiply parentheses ..

(+40x^2-72x+15x-27)-(6x-7)^2-(4(x^2-1))=0



We calculate terms in parentheses: -(4(x^2-1)), so:

4(x^2-1)

We multiply parentheses

4x^2-4

Back to the equation:

-(4x^2-4)



We get rid of parentheses

40x^2-4x^2-72x+15x-(6x-7)^2-27+4=0

We add all the numbers together, and all the variables

36x^2-57x-(6x-7)^2-23=0

We move all terms containing x to the left, all other terms to the right

36x^2-57x-(6x-7)^2=23

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